X^2-24x-145=0

Solution for X^2-24x-145=0 equation:

X^2-24X-145=0

a = 1; b = -24; c = -145;
Δ = b2-4ac
Δ = -242-4·1·(-145)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-34}{2*1}=\frac{-10}{2}
=-5
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+34}{2*1}=\frac{58}{2}
=29
$